中间值比大小

题目$\mathrm{比}\mathrm{较}{\log }_{5}2\mathrm{和}{0.7}^{0.4}$
解析
${\log }_{5}2<{\log }_5\sqrt{5}=\frac{1}{2}$
${0.7}^{0.4}>{0.5}^{0.4}>{0.5}^1=\frac{1}{2}$