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已知正实数满足已知正实数x满足(lgx)2025<(lgx)2024<(lgx)2026
令令a=lgx a2025<a2024⇒a2025−a2024=a2024(a−1)<0⇒a<1,a≠0 或a2026<a2024⇒a2026−a2024=a2024(a+1)(a−1)<0⇒a<−1或a>1 ∴a<−1 即即lgx<−1=lg10−1⇒0<x<110